智能车制作

标题: 51单片机 1602 求助 [打印本页]

作者: liuzhuoran1110 时间: 2011-11-24 17:31
标题: 51单片机 1602 求助
#define N 800 其它省略
sbit KEY = P3^4; //in
sbit KEY2 = P3^3; //out
sbit reset = P3^2; //0

void main()
{
uint sumin = 0;
uint sumout = 0;
uint in = 0;
uint out = 0;
uint arrin[3] = {0,1,2};
uint arrout[3] = {5,6,7};
uint i;

for (i = 3;i >= 0; i--)
{
arrin[i] = arrin[i] + '0';
}
for (i = 3; i >= 0; i--)
{
arrout[i] = arrout[i] + '0';
}
while(1)
{

L1602_init();
L1602_string(1,1,"enter:");
L1602_string(1,8,"out:");

L1602_string(2,1, arrin);
L1602_string(2,8, arrout);
delay_ms(N);

}
}

请问加上for (i = 3;i >= 0; i--)
{
arrin[i] = arrin[i] + '0';
}
for (i = 3; i >= 0; i--)
{
arrout[i] = arrout[i] + '0';
}就什么都不能输出，删掉就可以，为什么啊，
正如这里，我想输出L1602_string(2,1, arrin);
L1602_string(2,8, arrout);两个数组的值，应该如何修改，不胜感激啊！
驱动：void L1602_string(uchar hang,uchar lie,uchar *p)
{
uchar a,b=0;
if(hang == 1) a = 0x80;
if(hang == 2) a = 0xc0;
a = a + lie - 1;
while(1)
{
wcmd(a++);
b++;
if((*p == '\0')||(b==16)) break;
wdata(*p);
p++;
}
}

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