跪求线性ccd双峰法处理例程

小白菜的奋斗 · 发表于 2014-5-4 00:37:52

发到我邮箱962950706@qq.com 先谢过了，真在网上找不到例程

小鹿允2 · 发表于 2016-2-21 08:40:24

//-----------------------------------------前瞻是60cm-------------------------------------------
uint8 pixel2_min=40;
uint8 pixel2_max;
uint8 lad2=5;
uint8 ccd2_last_latch;
unsigned char white_value2=0;    //用于记录白色灰度的值
unsigned char black_value2=0;    //用于记录黑色灰度的值

//**************************************************************************************************
                           //双峰直方图测动态阀值
//**************************************************************************************************
uint8 ccd2_rere_left,ccd2_re_left;
uint8 black_latch2=0;
uint8 white_latch2=LATCH_LINE;//  white_latch=34
void get_latch2(void) //双峰直方图测动态阀值    //如ccd2_rere_left果出现问题，请检查电池是否有电
{
uint8 i=0;
pixel2_max=pixel2_min+lad2*34;
for (i=0;i<LATCH_LINE;i++)
   line_latch[i]=0;                      //灰度值数组初始化
for (i=8;i<=120;i++)                         //目前取的是从8到120个点
   if(pixel2[i]>pixel2_min&&pixel2[i]<pixel2_max)  //舍去太大或太小的点
      line_latch[(pixel2[i]-pixel2_min)/lad2]++;  //相应灰度值的组别对应的+1
total=line_latch[LATCH_LINE-1]+line_latch[LATCH_LINE-2]+line_latch[LATCH_LINE-3];
//白点方向的连续三组分布总和
for(i=LATCH_LINE-2;i>1;i--)  //找连续三组和最大的地方
{
   if(line_latch[i]+line_latch[i-1]+line_latch[i-2]>=total)
   {
      total=total+line_latch[i-2]-line_latch[i+1]; //向暗处移动，找白色的最大分布点
   }
   else
   {
      white_latch2=i; //此处为白线灰度
      break;
   }
}
total=line_latch[0]+line_latch[1]+line_latch[2]; //黑点方向的连续三组分布总和
for(i=1;i<LATCH_LINE-2;i++)
{
   if(line_latch[i]+line_latch[i+1]+line_latch[i+2]>=total)
   {
      total=total+line_latch[i+2]-line_latch[i-1];  //向亮处移动，找黑色的最大分布点
   }
   else
   {
      black_latch2=i; //此处为黑线灰度
      break;
   }
}
latch_space=char_abs(white_latch2-black_latch2);          //黑白峰间距
if(latch_space>=2)
{
      ccd2_latch=(black_latch2+white_latch2)/2;             //图像检测阀值
      //比较阀值数组附近的两组，得出数据点最少的一组作为阀值点
      latch1 = line_latch[ccd2_latch] < line_latch[ccd2_latch-1]? ccd2_latch:ccd2_latch-1;
      latch2 = line_latch[ccd2_latch] < line_latch[ccd2_latch+1]? ccd2_latch:ccd2_latch+1;
      ccd2_latch = line_latch[latch1]<line_latch[latch2]?latch1:latch2;
      ccd2_latch=ccd2_latch*lad2+pixel2_min+1;  //具体可能还需要进行调整
      ccd2_last_latch=ccd2_latch;
}
else
{
   ccd2_latch=ccd2_last_latch;
}
white_value2=white_latch2*lad2+pixel2_min;
black_value2=black_latch2*lad2+pixel2_min;
}